Set update() in Python to do union of n arrays
Last Updated :
21 Jul, 2022
We are given n arrays of any size which may have common elements, we need to combine all these arrays in such a way that each element should occurs only once and elements should be in sorted order? Examples:
Input : arr = [[1, 2, 2, 4, 3, 6],
[5, 1, 3, 4],
[9, 5, 7, 1],
[2, 4, 1, 3]]
Output : [1, 2, 3, 4, 5, 6, 7, 9]
A simple solution for this problem is to create a empty hash and traverse each array one by one, this hash contains frequency of each element in list of arrays. Now traverse hash from start and print each index which has non zero value. Here we solve this problem in python very quickly using properties of Set() data structure and Update() method in python.
How does Update() method works for set ?
anySet.update(iterable), this method does union of set named as anySet with any given iterable and it does not return any shallow copy of set like union() method, it updates the result into prefix set i.e; anySet.
Implementation:
Python3
def combineAll(input):
result = set(input[0])
for array in input[1:]:
result.update(array)
return list(result)
if __name__ == "__main__":
input = [[1, 2, 2, 4, 3, 6],
[5, 1, 3, 4],
[9, 5, 7, 1],
[2, 4, 1, 3]]
print (combineAll(input))
|
Output
[1, 2, 3, 4, 5, 6, 7, 9]
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