Python | Sort a tuple by its float element
Last Updated :
24 Dec, 2017
In this article, we will see how we can sort a tuple (consisting of float elements) using its float elements. Here we will see how to do this by using the built-in method sorted() and how can this be done using in place method of sorting.
Examples:
Input : tuple = [('lucky', '18.265'), ('nikhil', '14.107'),
('akash', '24.541'), ('anand', '4.256'), ('gaurav', '10.365')]
Output : [('akash', '24.541'), ('lucky', '18.265'),
('nikhil', '14.107'), ('gaurav', '10.365'), ('anand', '4.256')]
Input : tuple = [('234', '9.4'), ('543', '16.9'), ('756', '5.5'),
('132', '4.2'), ('342', '7.3')]
Output : [('543', '16.9'), ('234', '9.4'), ('342', '7.3'),
('756', '5.5'), ('132', '4.2')]
We can understand this from the image shown below:
Method 1 : Use of sorted() method
Sorted() sorts a tuple and always returns a tuple with the elements in a sorted manner, without modifying the original sequence. It takes three parameters from which two are optional, here we tried to use all of the three:
- Iterable : sequence (list, tuple, string) or collection (dictionary, set, frozenset) or any other iterator that needs to be sorted.
- Key(optional) : A function that would server as a key or a basis of sort comparison.
- Reverse(optional) : If set true, then the iterable would be sorted in reverse (descending) order, by default it is set as false.
To sort this in ascending order we could have just ignored the third parameter.
def Sort(tup):
return(sorted(tup, key = lambda x: float(x[1]), reverse = True))
tup = [('lucky', '18.265'), ('nikhil', '14.107'), ('akash', '24.541'),
('anand', '4.256'), ('gaurav', '10.365')]
print(Sort(tup))
|
Output:
[('akash', '24.541'), ('lucky', '18.265'), ('nikhil', '14.107'),
('gaurav', '10.365'), ('anand', '4.256')]
Method 2 : In-place way of sorting using sort():
While sorting via this method the actual content of the tuple is changed, while in the previous method the content of the original tuple remained the same.
def Sort(tup):
tup.sort(key = lambda x: float(x[1]), reverse = True)
print(tup)
tup = [('lucky', '18.265'), ('nikhil', '14.107'), ('akash', '24.541'),
('anand', '4.256'), ('gaurav', '10.365')]
Sort(tup)
|
Output:
[('akash', '24.541'), ('lucky', '18.265'), ('nikhil', '14.107'),
('gaurav', '10.365'), ('anand', '4.256')]
For more reference visit:
sorted() in Python
lambda in Python
Please Login to comment...