Python | Count occurrences of an element in a Tuple
Last Updated :
03 Nov, 2022
In this program, we need to accept a tuple and then find the number of times an item is present in the tuple. This can be done in various ways, but in this article, we will see how this can be done using a simple approach and how inbuilt functions can be used to solve this problem.
Examples:
Tuple: (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
Input : 4
Output : 0 times
Input : 10
Output : 3 times
Input : 8
Output : 4 times
Method 1(Simple Approach):
We keep a counter that keeps on increasing if the required element is found in the tuple.
Python3
def countX(tup, x):
count = 0
for ele in tup:
if (ele == x):
count = count + 1
return count
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8
print(countX(tup, enq))
print(countX(tup, enq1))
print(countX(tup, enq2))
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Method 2(Using count()):
The idea is to use method count() to count number of occurrences.
Python3
def Count(tup, en):
return tup.count(en)
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8
print(Count(tup, enq), "times")
print(Count(tup, enq1), "times")
print(Count(tup, enq2), "times")
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Output
0 times
3 times
4 times
Method 3: Using list comprehension
Python3
tuple1 = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x = [i for i in tuple1 if i == 10]
print("the element 10 occurs", len(x), "times")
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Output
the element 10 occurs 3 times
Method #4: Using enumerate function
Python3
tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=[i for a,i in enumerate(tuple1) if i==10]
print("the element 10 occurs",len(x),"times")
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Output
the element 10 occurs 3 times
Method #5: Using lambda function
Python3
tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=list(filter(lambda i: (i==10),tuple1))
print("the element 10 occurs",len(x),"times")
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Output
the element 10 occurs 3 times
Method #6: Using counter function
Python3
from collections import Counter
tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")
x=Counter(tuple1)
print("the element 10 occurs",x["10"],"times")
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Output
the element 10 occurs 3 times
Method#7: Using Countof function
Python3
tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")
import operator as op
print(op.countOf(tuple1,"10"))
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