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Python – Check if any list element is present in Tuple

Last Updated : 02 May, 2023
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Given a tuple, check if any list element is present in it.

Input : test_tup = (4, 5, 10, 9, 3), check_list = [6, 7, 10, 11] 
Output : True 
Explanation : 10 occurs in both tuple and list.

Input : test_tup = (4, 5, 12, 9, 3), check_list = [6, 7, 10, 11] 
Output : False 
Explanation : No common elements. 

Method #1: Using loop

In this, we keep a boolean variable, keeping record of all elements, if found, then returns True, else False.

Python3




# Python3 code to demonstrate working of
# Check if any list element is present in Tuple
# Using loop
 
# initializing tuple
test_tup = (4, 5, 7, 9, 3)
 
# printing original tuple
print("The original tuple is : " + str(test_tup))
 
# initializing list
check_list = [6, 7, 10, 11]
 
res = False
for ele in check_list:
     
    # checking using in operator
    if ele in test_tup :
        res = True
        break
 
# printing result
print("Is any list element present in tuple ? : " + str(res)) 






                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True




Time Complexity: O(n), where n is the length of the input list. 
Auxiliary Space: O(1) additional space is not required


Method #2: Using any()


This returns True, if any element of list is found in tuple, test using in operator.




Python3














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















# Python3 code to demonstrate working of 


# Check if any list element is present in Tuple


# Using any()


 


# initializing tuple


test_tup = (4, 5, 7, 9, 3)


 


# printing original tuple


print("The original tuple is : " + str(test_tup))


 


# initializing list 


check_list = [6, 7, 10, 11]


 


# generator expression is used for iteration 


res = any(ele in test_tup for ele in check_list)


 


# printing result 


print("Is any list element present in tuple ? : " + str(res)) 



















                        







                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True




Method #3: Using list comprehension




Python3














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















test_tup = (4, 5, 7, 9, 3)


check_list = [6, 7, 10, 11] 


x=["true" for i in check_list if i in test_tup] 


print(x)



















                        







                        










Output


['true']




Time complexity: O(n)


Auxiliary space: O(1)


Method #4: Using enumerate function




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test_tup = (4, 5, 7, 9, 3)


check_list = [6, 7, 10, 11] 


x=["true" for a,i in enumerate(check_list) if i in test_tup] 


print(x)



















                        







                        










Output


['true']




Method #5: Using lambda function




Python3














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















test_tup = (4, 5, 7, 9, 3)


check_list = [6, 7, 10, 11]  


x=list(filter(lambda i:(i in check_list),test_tup)) 


print(["true" if x else "false"])



















                        







                        










Output


['true']




Method #6: Using operator.countOf() method




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# Python3 code to demonstrate working of


# Check if any list element is present in Tuple


import operator as op


 


# initializing tuple


test_tup = (4, 5, 7, 9, 3)


 


# printing original tuple


print("The original tuple is : " + str(test_tup))


 


# initializing list


check_list = [6, 7, 10, 11]


 


res = False


for ele in check_list:


 


    # checking using in operator


    if op.countOf(test_tup, ele) > 0:


        res = True


        break


 


# printing result


print("Is any list element present in tuple ? : " + str(res))



















                        







                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True




Time Complexity: O(N)
Auxiliary Space : O(1)


Method #7: Using any() + map() function




Python3














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















# Python3 code to demonstrate working of 


# Check if any list element is present in Tuple


# Using any() + map() function


 


# initializing tuple


test_tup = (4, 5, 7, 9, 3)


 


# printing original tuple


print("The original tuple is : " + str(test_tup))


 


# initializing list 


check_list = [6, 7, 10, 11]


 


# using any() + map() function


res = any(map(lambda x: x in test_tup, check_list))


 


# printing result


print("Is any list element present in tuple ? : " + str(res))


#This code is contributed by Vinay Pinjala.



















                        







                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True




Time Complexity: O(N)
Auxiliary Space : O(1)


Method#8: Using Recursive method.




Python3














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















# Python3 code to demonstrate working of


# Check if any list element is present in Tuple


 


def is_element_present(test_tup, check_list):


    if not check_list:


        return False


    if check_list[0] in test_tup:


        return True


    return is_element_present(test_tup, check_list[1:])


 


# initializing tuple


test_tup = (4, 5, 7, 9, 3)


 


# printing original tuple


print("The original tuple is : " + str(test_tup))


 


# initializing list


check_list = [6, 7, 10, 11]


 


# printing result


print("Is any list element present in tuple ? : " + str(is_element_present(test_tup, check_list)))


#this code contributed by tvsk



















                        







                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True




Time Complexity: O(n)


Space Complexity: O(n)


Method 11: Using while loop and in operator:


Approach:


    

  • Initialize the test_list. 
    • 

  • Initialize the check_list.
    • 

  • Initialize the boolean variable that contains result.
    • 

  • Initialize ‘i’ variable that contains the length of the list.
    • 

  • While loop iterate ‘i’ times.
    • 

  • Inside while loop checks the condition element at the index ‘i’ present in the tuple or not. 
    • 

  • If the element is present in the tuple break the loop and print True for the result. 
    • 

  • Else print False for the result. 
    • 





Python














                                    




                                    

                                    




                                    




                                    

                                    

                                    
                                




















# Python3 code to demonstrate working of


# Check if any list element is present in Tuple


# Using loop


 


# initializing tuple


test_tup = (4, 5, 7, 9, 3)


 


# printing original tuple


print("The original tuple is : " + str(test_tup))


 


# initializing list


check_list = [6, 7, 10, 11]


 


# Variable to store result and length of list


res = False


i = len(check_list) - 1


 


#Checking presence of element


while i >= 0:


     


    # checking using in operator


    if check_list[i] in test_tup :


        res = True


        break


    i = i - 1


 


# printing result


print("Is any list element present in tuple ? : " + str(res))



















                        







                        










Output


The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True





Time Complexity: O(N), where N is the length of the list
Auxiliary Space: O(N)




                                    


                                                                        

                                        

                                            

                                                

                                                    
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                                                    manjeet_04                                                

                                            

                                            

            
                                        

                                        

                                            
    

        
        
    
                                            

                                                
                                                
                                            

                                            

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