Multilevel Linked List

Last Updated : 25 Feb, 2023

Multilevel Linked List
Multilevel Linked List is a 2D data structure that comprises several linked lists and each node in a multilevel linked list has a next and child pointer. All the elements are linked using pointers.

multilevel linked list

Representation:
A multilevel linked list is represented by a pointer to the first node of the linked lists. Similar to the linked list, the first node is called the head. If the multilevel linked list is empty, then the value of head is NULL. Each node in a list consists of at least three parts:
1. Data.
2. Pointer to the next node.
3. Pointer to the child node.

Each node of a multilevel linked list is represented as:

class Node
{
public:
int data;
Node *next;
Node *child;
};

Below is the implementation of the multilevel linked list

C++

// C++ program to implement
// a multilevel linked list
 
#include <bits/stdc++.h>
using namespace std;
 
// Representation of node
class Node {
public:
    int data;
    Node* next;
    Node* child;
};
 
// A function to create a linked list
// with n(size) nodes returns head pointer
Node* createList(int* arr, int n)
{
    Node* head = NULL;
    Node* tmp;
 
    // Traversing the passed array
    for (int i = 0; i < n; i++) {
        // Creating a node if the list
        // is empty
        if (head == NULL) {
            tmp = head = new Node();
        }
        else {
            tmp->next = new Node();
            tmp = tmp->next;
        }
        // Created a node with data and
        // setting child and next pointer
        // as NULL.
        tmp->data = arr[i];
        tmp->next = tmp->child = NULL;
    }
    return head;
}
 
// To print the linked list
void printMultiLevelList(Node* head)
{
    // While head is not null
    while (head) {
        if (head->child) {
            printMultiLevelList(head->child);
        }
        cout << head->data << " ";
        head = head->next;
    }
}
 
// Driver code
int main()
{
    // Initializing the data in arrays(row wise)
    int arr1[3] = { 1, 2, 3 };
    int arr2[2] = { 5, 6 };
    int arr3[1] = { 4 };
    int arr4[3] = { 7, 8, 9 };
 
    // creating Four linked lists
    // Passing array and size of array
    // as parameters
    Node* head1 = createList(arr1, 3);
    Node* head2 = createList(arr2, 2);
    Node* head3 = createList(arr3, 1);
    Node* head4 = createList(arr4, 3);
 
    // Initializing children and next pointers
    // as shown in given diagram
    head1->child = head2;
    head1->next->next->child = head3;
    head2->next->child = head4;
 
    // Creating a null pointer.
    Node* head = NULL;
    head = head1;
 
    // Function Call to print
    printMultiLevelList(head);
 
    return 0;
}

Java

// Java program to implement
// a multilevel linked list
 
 
public class GFG {
     
      // Representation of node
    public static class Node {
        public int data;
        public Node next;
        public Node child;
 
        public Node(int data) {
            this.data = data;
            this.next = null;
            this.child = null;
        }
    }
     
   
      // A function to create a linked list
    // with n(size) nodes returns head pointer
    public static Node createList(int[] arr, int n) {
        Node head = null;
        Node tmp = null;
         
      // Traversing the passed array
        for (int i = 0; i < n; i++) {
               // Creating a node if the list
                // is empty
            if (head == null) {
                tmp = head = new Node(arr[i]);
            } else {
                   
                  // Created a node with data and
                // setting child and next pointer
                // as NULL.
                tmp.next = new Node(arr[i]);
                tmp = tmp.next;
            }
        }
 
        return head;
    }
     
       
// To print the linked list
    public static void printMultiLevelList(Node head) {    
          // While head is not null
        while (head != null) {
            if (head.child != null) {
                printMultiLevelList(head.child);
            }
            System.out.print(head.data + " ");
            head = head.next;
        }
    }
 
    public static void main(String[] args) {
           
      // Initializing the data in arrays(row wise)
        int[] arr1 = {1, 2, 3};
        int[] arr2 = {5, 6};
        int[] arr3 = {4};
        int[] arr4 = {7, 8, 9};
         
           // creating Four linked lists
        // Passing array and size of array
        // as parameters
        Node head1 = createList(arr1, 3);
        Node head2 = createList(arr2, 2);
        Node head3 = createList(arr3, 1);
        Node head4 = createList(arr4, 3);
         
          // Initializing children and next pointers
           // as shown in given diagram
        head1.child = head2;
        head1.next.next.child = head3;
        head2.next.child = head4;
         
          // Creating a null pointer.
        Node head = head1;
           
       
           // Function Call to print
        printMultiLevelList(head);
    }
}
 
// this code is contributed by bhardwajji

Python3

'''package whatever #do not write package name here '''
class Node: 
    def __init__(self):
        self.data = 0; 
        self.next = None;
        self.child = None;
 
# A function to create a linked list
# with n(size) Nodes returns head pointer
def createList(arr, n):
    head = None;
    tmp = None;
 
    # Traversing the passed array
    for i in range(n):
 
        # Creating a Node if the list
        # is empty
        if (head == None):
            tmp = head = Node();
        else:
            tmp.next = Node();
            tmp = tmp.next;
         
        # Created a Node with data and
        # setting child and next pointer
        # as NULL.
        tmp.data = arr[i];
        tmp.next = tmp.child = None;
     
    return head;
 
# To print linked list
def printMultiLevelList(head):
 
    # While head is not None
    while (head != None):
        if (head.child != None):
            printMultiLevelList(head.child);
         
        print(head.data, end=" ");
        head = head.next;
     
# Driver code
if __name__ == '__main__':
    arr1 = [ 1, 2, 3 ];
    arr2 = [ 5, 6] ;
    arr3 = [ 4 ];
    arr4 = [ 7, 8, 9] ;
 
    # creating Four linked lists
    # Passing array and size of array
    # as parameters
    head1 = createList(arr1, 3);
    head2 = createList(arr2, 2);
    head3 = createList(arr3, 1);
    head4 = createList(arr4, 3);
 
    # Initializing children and next pointers
    # as shown in given diagram
    head1.child = head2;
    head1.next.next.child = head3;
    head2.next.child = head4;
 
    # Creating a None pointer.
    head = None;
    head = head1;
 
    # Function Call to print
    printMultiLevelList(head);
 
# This code is contributed by umadevi9616 

C#

/*package whatever //do not write package name here */
using System;
 
public class GFG {
   public class Node {
          public int data;
        public Node next;
        public Node child;
    };
 
    // A function to create a linked list
    // with n(size) nodes returns head pointer
    public static Node createList(int []arr, int n)
    {
        Node head = null;
        Node tmp = null;
 
        // Traversing the passed array
        for (int i = 0; i < n; i++)
        {
           
            // Creating a node if the list
            // is empty
            if (head == null) {
                tmp = head = new Node();
            }
            else {
                tmp.next = new Node();
                tmp = tmp.next;
            }
           
            // Created a node with data and
            // setting child and next pointer
            // as NULL.
            tmp.data = arr[i];
            tmp.next = tmp.child = null;
        }
        return head;
    }
 
    // To print the linked list
    public static void printMultiLevelList(Node head)
    {
       
        // While head is not null
        while (head != null) {
            if (head.child != null) {
                printMultiLevelList(head.child);
            }
            Console.Write(head.data + " ");
            head = head.next;
        }
    }
 
    // Driver code
    public static void Main(String[] args)
    {
        int []arr1 = { 1, 2, 3 };
        int []arr2 = { 5, 6 };
        int []arr3 = { 4 };
        int []arr4 = { 7, 8, 9 };
 
        // creating Four linked lists
        // Passing array and size of array
        // as parameters
        Node head1 = createList(arr1, 3);
        Node head2 = createList(arr2, 2);
        Node head3 = createList(arr3, 1);
        Node head4 = createList(arr4, 3);
 
        // Initializing children and next pointers
        // as shown in given diagram
        head1.child = head2;
        head1.next.next.child = head3;
        head2.next.child = head4;
 
        // Creating a null pointer.
        Node head = null;
        head = head1;
 
        // Function Call to print
        printMultiLevelList(head);
    }
}
 
// This code is contributed by shikhasingrajput

Javascript

<script>
/*package whatever //do not write package name here */
    class Node {
        constructor(){
      this.data = 0;
        this.next = null;
        this.child = null;
        }
    }
 
    // A function to create a linked list
    // with n(size) nodes returns head pointer
    function createList(arr , n)
    {
        var head = null;
        var tmp = null;
 
        // Traversing the passed array
        for (var i = 0; i < n; i++)
        {
           
            // Creating a node if the list
            // is empty
            if (head == null) {
                tmp = head = new Node();
            }
            else {
                tmp.next = new Node();
                tmp = tmp.next;
            }
           
            // Created a node with data and
            // setting child and next pointer
            // as NULL.
            tmp.data = arr[i];
            tmp.next = tmp.child = null;
        }
        return head;
    }
 
    // To print the linked list
    function printMultiLevelList(head)
    {
       
        // While head is not null
        while (head != null) {
            if (head.child != null) {
                printMultiLevelList(head.child);
            }
            document.write(head.data + " ");
            head = head.next;
        }
    }
 
    // Driver code
 
        var arr1 = [ 1, 2, 3 ];
        var arr2 = [ 5, 6 ];
        var arr3 = [ 4 ];
        var arr4 = [ 7, 8, 9 ];
 
        // creating Four linked lists
        // Passing array and size of array
        // as parameters
        var head1 = createList(arr1, 3);
        var head2 = createList(arr2, 2);
        var head3 = createList(arr3, 1);
        var head4 = createList(arr4, 3);
 
        // Initializing children and next pointers
        // as shown in given diagram
        head1.child = head2;
        head1.next.next.child = head3;
        head2.next.child = head4;
 
        // Creating a null pointer.
        var head = null;
        head = head1;
 
        // Function Call to print
        printMultiLevelList(head);
 
// This code is contributed by Rajput-Ji 
</script>

Output

5 7 8 9 6 1 2 4 3

anuragsingh1022

Improve

Flatten a multilevel linked list

Multilevel Linked List

C++

Java

Python3

C#

Javascript

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