Python – AND operation between Tuples

Last Updated : 23 Apr, 2023

Sometimes, while working with records, we might have a common problem of performing AND operation contents of one tuple with corresponding index of other tuple. This has application in almost all the domains in which we work with tuple records especially Data Science. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using map() + lambda Combination of above functionalities can solve the problem for us. In this, we compute the AND using lambda functions and extend the logic to keys using map().

Python3

# Python3 code to demonstrate working of
# Cross Tuple AND operation
# using map() + lambda
 
# initialize tuples 
test_tup1 = (10, 4, 5)
test_tup2 = (2, 5, 18)
 
# printing original tuples 
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
 
# Cross Tuple AND operation
# using map() + lambda
res = tuple(map(lambda i, j: i & j, test_tup1, test_tup2))
 
# printing result
print("Resultant tuple after AND operation : " + str(res))

Output :

The original tuple 1 : (10, 4, 5)
The original tuple 2 : (2, 5, 18)
Resultant tuple after AND operation : (2, 4, 0)

Method #2 : Using map() + iand() The combination of above functions can help us achieve this task. In this, we first extend the logic to all using map() and then perform AND of each index using iand().

Python3

# Python3 code to demonstrate working of
# Cross Tuple AND operation
# using map() + iand()
import operator
 
# initialize tuples 
test_tup1 = (10, 4, 5)
test_tup2 = (2, 5, 18)
 
# printing original tuples 
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
 
# Cross Tuple AND operation
# using map() + iand()
res = tuple(map(operator.iand, test_tup1, test_tup2))
 
# printing result
print("Resultant tuple after AND operation : " + str(res))

Output :

The original tuple 1 : (10, 4, 5)
The original tuple 2 : (2, 5, 18)
Resultant tuple after AND operation : (2, 4, 0)

Method #3: Using List comprehension

This approach is similar to the previous ones but uses a more concise and readable syntax using list comprehension.

Python3

# Python3 code to demonstrate working of
# Cross Tuple AND operation
# using List comprehension
 
# initialize tuples 
test_tup1 = (10, 4, 5)
test_tup2 = (2, 5, 18)
   
# printing original tuples 
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
   
# Cross Tuple AND operation
# using List comprehension
res = tuple([i & j for i,j in zip(test_tup1, test_tup2)])
   
# printing result
print("Resultant tuple after AND operation : " + str(res))
#This code is contributed by Edula Vinay Kumar Reddy

Output

The original tuple 1 : (10, 4, 5)
The original tuple 2 : (2, 5, 18)
Resultant tuple after AND operation : (2, 4, 0)

Time complexity: O(n) where n is the length of the tuples
Auxiliary Space: O(n) as we are creating a new tuple of the same size as the input tuples

Method #4: Using zip():

Python3

test_tup1 = (10, 4, 5)
test_tup2 = (2, 5, 18)
# printing original tuples
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
res = tuple([i & j for i, j in zip(test_tup1, test_tup2)])
print(res)
#This code is contributed by Jyothi pinjala

Output

The original tuple 1 : (10, 4, 5)
The original tuple 2 : (2, 5, 18)
(2, 4, 0)

Time complexity: O(n)
Space complexity: O(n)

Method #5: Using a for loop

Step-by-step approach:

Initialize an empty list called result.
Iterate over the indices of the input tuples using the range() function.
Compute the bitwise AND of the corresponding elements of the input tuples using the & operator.
Append the result to the result list.
Convert the result list to a tuple using the tuple() function.
Return the tuple.

Python3

def bitwise_and_tuples(tup1, tup2):
    result = []
    for i in range(len(tup1)):
        result.append(tup1[i] & tup2[i])
    return tuple(result)
test_tup1 = (10, 4, 5)
test_tup2 = (2, 5, 18)
res = bitwise_and_tuples(test_tup1, test_tup2)
print(res)