Next Greater Element (NGE) for every element in given Array
Last Updated :
12 Jun, 2024
Given an array, print the Next Greater Element (NGE) for every element.
The Next greater Element for an element x is the first greater element on the right side of x in the array. Elements for which no greater element exist, consider the next greater element as -1.
Examples:
Input: arr[] = [ 4 , 5 , 2 , 25 ]
Output: 4 –> 5
5 –> 25
2 –> 25
25 –> -1
Explanation: except 25 every element has an element greater than them present on the right side
Input: arr[] = [ 13 , 7, 6 , 12 ]
Output: 13 –> -1
7 –> 12
6 –> 12
12 –> -1
Explanation: 13 and 12 don’t have any element greater than them present on the right side
The idea is to use two loops , The outer loop picks all the elements one by one. The inner loop looks for the first greater element for the element picked by the outer loop. If a greater element is found then that element is printed as next, otherwise, -1 is printed.
Follow the steps mentioned below to implement the idea:
- Traverse the array from index 0 to end.
- For each element start another loop from index i+1 to end.
- If a greater element is found in the second loop then print it and break the loop, else print -1.
Below is the implementation of the above approach:
C++
// Simple C++ program to print
// next greater elements in a
// given array
#include <iostream>
using namespace std;
/* prints element and NGE pair
for all elements of arr[] of size n */
void printNGE(int arr[], int n)
{
int next, i, j;
for (i = 0; i < n; i++) {
next = -1;
for (j = i + 1; j < n; j++) {
if (arr[i] < arr[j]) {
next = arr[j];
break;
}
}
cout << arr[i] << " --> " << next << endl;
}
}
// Driver Code
int main()
{
int arr[] = { 11, 13, 21, 3 };
int n = sizeof(arr) / sizeof(arr[0]);
printNGE(arr, n);
return 0;
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
C
// Simple C program to print next greater elements
// in a given array
#include <stdio.h>
/* prints element and NGE pair for all elements of
arr[] of size n */
void printNGE(int arr[], int n)
{
int next, i, j;
for (i = 0; i < n; i++) {
next = -1;
for (j = i + 1; j < n; j++) {
if (arr[i] < arr[j]) {
next = arr[j];
break;
}
}
printf("%d -- %dn", arr[i], next);
}
}
int main()
{
int arr[] = { 11, 13, 21, 3 };
int n = sizeof(arr) / sizeof(arr[0]);
printNGE(arr, n);
return 0;
}
Java
// Simple Java program to print next
// greater elements in a given array
class Main {
/* prints element and NGE pair for
all elements of arr[] of size n */
static void printNGE(int arr[], int n)
{
int next, i, j;
for (i = 0; i < n; i++) {
next = -1;
for (j = i + 1; j < n; j++) {
if (arr[i] < arr[j]) {
next = arr[j];
break;
}
}
System.out.println(arr[i] + " -- " + next);
}
}
public static void main(String args[])
{
int arr[] = { 11, 13, 21, 3 };
int n = arr.length;
printNGE(arr, n);
}
}
Python
# Function to print element and NGE pair for all elements of list
def printNGE(arr):
for i in range(0, len(arr), 1):
next = -1
for j in range(i+1, len(arr), 1):
if arr[i] < arr[j]:
next = arr[j]
break
print(str(arr[i]) + " -- " + str(next))
# Driver program to test above function
arr = [11, 13, 21, 3]
printNGE(arr)
# This code is contributed by Sunny Karira
C#
// Simple C# program to print next
// greater elements in a given array
using System;
class GFG {
/* prints element and NGE pair for
all elements of arr[] of size n */
static void printNGE(int[] arr, int n)
{
int next, i, j;
for (i = 0; i < n; i++) {
next = -1;
for (j = i + 1; j < n; j++) {
if (arr[i] < arr[j]) {
next = arr[j];
break;
}
}
Console.WriteLine(arr[i] + " -- " + next);
}
}
// driver code
public static void Main()
{
int[] arr = { 11, 13, 21, 3 };
int n = arr.Length;
printNGE(arr, n);
}
}
// This code is contributed by Sam007
Javascript
<script>
// Simple JavaScript program to print
// next greater elements in a
// given array
/* prints element and NGE pair
for all elements of arr[] of size n */
function printNGE(arr, n)
{
var next, i, j;
for (i = 0; i < n; i++)
{
next = -1;
for (j = i + 1; j < n; j++)
{
if (arr[i] < arr[j])
{
next = arr[j];
break;
}
}
document.write(arr[i] + " -- " + next);
document.write("<br>");
}
}
// Driver Code
var arr = [11, 13, 21, 3];
var n = arr.length;
printNGE(arr, n);
// This code is contributed by rdtank.
</script>
PHP
<?php
// Simple PHP program to print next
// greater elements in a given array
/* prints element and NGE pair for
all elements of arr[] of size n */
function printNGE($arr, $n)
{
for ($i = 0; $i < $n; $i++)
{
$next = -1;
for ($j = $i + 1; $j < $n; $j++)
{
if ($arr[$i] < $arr[$j])
{
$next = $arr[$j];
break;
}
}
echo $arr[$i]." -- ". $next."\n";
}
}
// Driver Code
$arr= array(11, 13, 21, 3);
$n = count($arr);
printNGE($arr, $n);
// This code is contributed by Sam007
?>
Output11 --> 13
13 --> 21
21 --> -1
3 --> -1
Time Complexity: O(N2)
Auxiliary Space: O(1)
Find Next Greater Element using Stack:
The idea is to store the elements for which we have to find the next greater element in a stack and while traversing the array, if we find a greater element, we will pair it with the elements from the stack till the top element of the stack is less than the current element.
Illustration:
Below is the illustration of the above approach:
Follow the steps mentioned below to implement the idea:
- Push the first element to stack.
- Pick the rest of the elements one by one and follow the following steps in the loop.
- Mark the current element as next.
- If the stack is not empty, compare top most element of stack with next.
- If next is greater than the top element, Pop element from the stack. next is the next greater element for the popped element.
- Keep popping from the stack while the popped element is smaller than next. next becomes the next greater element for all such popped elements.
- Finally, push the next in the stack.
- After the loop in step 2 is over, pop all the elements from the stack and print -1 as the next element for them.
Below is the implementation of the above approach:
C++
// A Stack based C++ program to find next
// greater element for all array elements.
#include <bits/stdc++.h>
using namespace std;
/* prints element and NGE pair for all
elements of arr[] of size n */
void printNGE(int arr[], int n)
{
stack<int> s;
/* push the first element to stack */
s.push(arr[0]);
// iterate for rest of the elements
for (int i = 1; i < n; i++) {
if (s.empty()) {
s.push(arr[i]);
continue;
}
/* if stack is not empty, then
pop an element from stack.
If the popped element is smaller
than next, then
a) print the pair
b) keep popping while elements are
smaller and stack is not empty */
while (s.empty() == false && s.top() < arr[i]) {
cout << s.top() << " --> " << arr[i] << endl;
s.pop();
}
/* push next to stack so that we can find
next greater for it */
s.push(arr[i]);
}
/* After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them */
while (s.empty() == false) {
cout << s.top() << " --> " << -1 << endl;
s.pop();
}
}
/* Driver code */
int main()
{
int arr[] = { 11, 13, 21, 3 };
int n = sizeof(arr) / sizeof(arr[0]);
printNGE(arr, n);
return 0;
}
C
// A Stack based C program to find next
// greater element for all array elements.
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#define STACKSIZE 100
// stack structure
struct stack {
int top;
int items[STACKSIZE];
};
// Stack Functions to be used by printNGE()
void push(struct stack* ps, int x)
{
if (ps->top == STACKSIZE - 1) {
printf("Error: stack overflown");
getchar();
exit(0);
}
else {
ps->top += 1;
int top = ps->top;
ps->items[top] = x;
}
}
bool isEmpty(struct stack* ps)
{
return (ps->top == -1) ? true : false;
}
int pop(struct stack* ps)
{
int temp;
if (ps->top == -1) {
printf("Error: stack underflow n");
getchar();
exit(0);
}
else {
int top = ps->top;
temp = ps->items[top];
ps->top -= 1;
return temp;
}
}
/* prints element and NGE pair for all elements of
arr[] of size n */
void printNGE(int arr[], int n)
{
int i = 0;
struct stack s;
s.top = -1;
int element, next;
/* push the first element to stack */
push(&s, arr[0]);
// iterate for rest of the elements
for (i = 1; i < n; i++) {
next = arr[i];
if (isEmpty(&s) == false) {
// if stack is not empty, then pop an element
// from stack
element = pop(&s);
/* If the popped element is smaller than next,
then a) print the pair b) keep popping while
elements are smaller and stack is not empty
*/
while (element < next) {
printf("n %d --> %d", element, next);
if (isEmpty(&s) == true)
break;
element = pop(&s);
}
/* If element is greater than next, then push
the element back */
if (element > next)
push(&s, element);
}
/* push next to stack so that we can find
next greater for it */
push(&s, next);
}
/* After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them */
while (isEmpty(&s) == false) {
element = pop(&s);
next = -1;
printf("n %d --> %d", element, next);
}
}
/* Driver code */
int main()
{
int arr[] = { 11, 13, 21, 3 };
int n = sizeof(arr) / sizeof(arr[0]);
printNGE(arr, n);
getchar();
return 0;
}
Java
// Java program to print next
// greater element using stack
public class NGE {
static class stack {
int top;
int items[] = new int[100];
// Stack functions to be used by printNGE
void push(int x)
{
if (top == 99) {
System.out.println("Stack full");
}
else {
items[++top] = x;
}
}
int pop()
{
if (top == -1) {
System.out.println("Underflow error");
return -1;
}
else {
int element = items[top];
top--;
return element;
}
}
boolean isEmpty()
{
return (top == -1) ? true : false;
}
}
/* prints element and NGE pair for
all elements of arr[] of size n */
static void printNGE(int arr[], int n)
{
int i = 0;
stack s = new stack();
s.top = -1;
int element, next;
/* push the first element to stack */
s.push(arr[0]);
// iterate for rest of the elements
for (i = 1; i < n; i++) {
next = arr[i];
if (s.isEmpty() == false) {
// if stack is not empty, then
// pop an element from stack
element = s.pop();
/* If the popped element is smaller than
next, then a) print the pair b) keep
popping while elements are smaller and
stack is not empty */
while (element < next) {
System.out.println(element + " --> "
+ next);
if (s.isEmpty() == true)
break;
element = s.pop();
}
/* If element is greater than next, then
push the element back */
if (element > next)
s.push(element);
}
/* push next to stack so that we can find next
greater for it */
s.push(next);
}
/* After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them */
while (s.isEmpty() == false) {
element = s.pop();
next = -1;
System.out.println(element + " -- " + next);
}
}
// Driver Code
public static void main(String[] args)
{
int arr[] = { 11, 13, 21, 3 };
int n = arr.length;
printNGE(arr, n);
}
}
// Thanks to Rishabh Mahrsee for contributing this code
Python
# Python program to print next greater element using stack
# Stack Functions to be used by printNGE()
def createStack():
stack = []
return stack
def isEmpty(stack):
return len(stack) == 0
def push(stack, x):
stack.append(x)
def pop(stack):
if isEmpty(stack):
print("Error : stack underflow")
else:
return stack.pop()
'''prints element and NGE pair for all elements of
arr[] '''
def printNGE(arr):
s = createStack()
element = 0
next = 0
# push the first element to stack
push(s, arr[0])
# iterate for rest of the elements
for i in range(1, len(arr), 1):
next = arr[i]
if isEmpty(s) == False:
# if stack is not empty, then pop an element from stack
element = pop(s)
'''If the popped element is smaller than next, then
a) print the pair
b) keep popping while elements are smaller and
stack is not empty '''
while element < next:
print(str(element) + " -- " + str(next))
if isEmpty(s) == True:
break
element = pop(s)
'''If element is greater than next, then push
the element back '''
if element > next:
push(s, element)
'''push next to stack so that we can find
next greater for it '''
push(s, next)
'''After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them '''
while isEmpty(s) == False:
element = pop(s)
next = -1
print(str(element) + " -- " + str(next))
# Driver code
arr = [11, 13, 21, 3]
printNGE(arr)
# This code is contributed by Sunny Karira
C#
using System;
// c# program to print next
// greater element using stack
public class NGE {
public class stack {
public int top;
public int[] items = new int[100];
// Stack functions to be used by printNGE
public virtual void push(int x)
{
if (top == 99) {
Console.WriteLine("Stack full");
}
else {
items[++top] = x;
}
}
public virtual int pop()
{
if (top == -1) {
Console.WriteLine("Underflow error");
return -1;
}
else {
int element = items[top];
top--;
return element;
}
}
public virtual bool Empty
{
get { return (top == -1) ? true : false; }
}
}
/* prints element and NGE pair for
all elements of arr[] of size n */
public static void printNGE(int[] arr, int n)
{
int i = 0;
stack s = new stack();
s.top = -1;
int element, next;
/* push the first element to stack */
s.push(arr[0]);
// iterate for rest of the elements
for (i = 1; i < n; i++) {
next = arr[i];
if (s.Empty == false) {
// if stack is not empty, then
// pop an element from stack
element = s.pop();
/* If the popped element is smaller than
next, then a) print the pair b) keep
popping while elements are smaller and
stack is not empty */
while (element < next) {
Console.WriteLine(element + " --> "
+ next);
if (s.Empty == true) {
break;
}
element = s.pop();
}
/* If element is greater than next, then
push the element back */
if (element > next) {
s.push(element);
}
}
/* push next to stack so that we can find next
greater for it */
s.push(next);
}
/* After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them */
while (s.Empty == false) {
element = s.pop();
next = -1;
Console.WriteLine(element + " -- " + next);
}
}
// Driver Code
public static void Main(string[] args)
{
int[] arr = new int[] { 11, 13, 21, 3 };
int n = arr.Length;
printNGE(arr, n);
}
}
// This code is contributed by Shrikant13
Javascript
<script>
// A Stack based Javascript program to find next
// greater element for all array elements.
/* prints element and NGE pair for all
elements of arr[] of size n */
function printNGE(arr, n)
{
var s = [];
/* push the first element to stack */
s.push(arr[0]);
// iterate for rest of the elements
for (var i = 1; i < n; i++)
{
if (s.length == 0) {
s.push(arr[i]);
continue;
}
/* if stack is not empty, then
pop an element from stack.
If the popped element is smaller
than next, then
a) print the pair
b) keep popping while elements are
smaller and stack is not empty */
while (s.length ==0 == false
&& s[s.length-1] < arr[i])
{
document.write( s[s.length-1]
+ " --> " + arr[i]+"<br>");
s.pop();
}
/* push next to stack so that we can find
next greater for it */
s.push(arr[i]);
}
/* After iterating over the loop, the remaining
elements in stack do not have the next greater
element, so print -1 for them */
while (s.length !=0) {
document.write( s[s.length-1] + " --> " + -1+ "<br>" );
s.pop();
}
}
/* Driver code */
var arr = [11, 13, 21, 3];
var n = arr.length;
printNGE(arr, n);
</script>
Output11 --> 13
13 --> 21
3 --> -1
21 --> -1
Time Complexity: O(N)
Auxiliary Space: O(N)
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