Paths to travel each nodes using each edge (Seven Bridges of Königsberg)

Last Updated : 11 Mar, 2023

There are n nodes and m bridges in between these nodes. Print the possible path through each node using each edges (if possible), traveling through each edges only once.

Examples :

Input : [[0, 1, 0, 0, 1],
         [1, 0, 1, 1, 0],
         [0, 1, 0, 1, 0],
         [0, 1, 1, 0, 0],
         [1, 0, 0, 0, 0]]

Output : 5 -> 1 -> 2 -> 4 -> 3 -> 2

Input : [[0, 1, 0, 1, 1],
         [1, 0, 1, 0, 1],
         [0, 1, 0, 1, 1],
         [1, 1, 1, 0, 0],
         [1, 0, 1, 0, 0]]

Output : "No Solution"

It is one of the famous problems in Graph Theory and known as problem of “Seven Bridges of Königsberg”. This problem was solved by famous mathematician Leonhard Euler in 1735. This problem is also considered as the beginning of Graph Theory.

The problem back then was that: There was 7 bridges connecting 4 lands around the city of Königsberg in Prussia. Was there any way to start from any of the land and go through each of the bridges once and only once? Please see these wikipedia images for more clarity.

Euler first introduced graph theory to solve this problem. He considered each of the lands as a node of a graph and each bridge in between as an edge in between. Now he calculated if there is any Eulerian Path in that graph. If there is an Eulerian path then there is a solution otherwise not.
Problem here, is a generalized version of the problem in 1735.

Below is the implementation :

C++

// A C++ program print Eulerian Trail in a
// given Eulerian or Semi-Eulerian Graph
#include <iostream>
#include <string.h>
#include <algorithm>
#include <list>
using namespace std;
 
// A class that represents an undirected graph
class Graph
{
// No. of vertices
    int V;
 
    // A dynamic array of adjacency lists
    list<int> *adj;
public:
 
    // Constructor and destructor
    Graph(int V)
    {
        this->V = V;
        adj = new list<int>[V];
    }
    ~Graph()
    {
        delete [] adj;
    }
 
    // functions to add and remove edge
    void addEdge(int u, int v)
    {
        adj[u].push_back(v);
        adj[v].push_back(u);
    }
 
    void rmvEdge(int u, int v);
 
    // Methods to print Eulerian tour
    void printEulerTour();
    void printEulerUtil(int s);
 
    // This function returns count of vertices
    // reachable from v. It does DFS
    int DFSCount(int v, bool visited[]);
 
    // Utility function to check if edge u-v
    // is a valid next edge in Eulerian trail or circuit
    bool isValidNextEdge(int u, int v);
};
 
/* The main function that print Eulerian Trail.
It first finds an odd degree vertex (if there is any)
and then calls printEulerUtil() to print the path */
void Graph::printEulerTour()
{
    // Find a vertex with odd degree
    int u = 0;
 
    for (int i = 0; i < V; i++)
        if (adj[i].size() & 1)
        {
            u = i;
            break;
        }
 
    // Print tour starting from oddv
    printEulerUtil(u);
    cout << endl;
}
 
// Print Euler tour starting from vertex u
void Graph::printEulerUtil(int u)
{
 
    // Recur for all the vertices adjacent to
    // this vertex
    list<int>::iterator i;
    for (i = adj[u].begin(); i != adj[u].end(); ++i)
    {
        int v = *i;
 
        // If edge u-v is not removed and it's a
        // valid next edge
        if (v != -1 && isValidNextEdge(u, v))
        {
            cout << u << "-" << v << " ";
            rmvEdge(u, v);
            printEulerUtil(v);
        }
    }
}
 
// The function to check if edge u-v can be considered
// as next edge in Euler Tout
bool Graph::isValidNextEdge(int u, int v)
{
 
    // The edge u-v is valid in one of the following
    // two cases:
 
    // 1) If v is the only adjacent vertex of u
    int count = 0; // To store count of adjacent vertices
    list<int>::iterator i;
    for (i = adj[u].begin(); i != adj[u].end(); ++i)
        if (*i != -1)
            count++;
    if (count == 1)
        return true;
 
 
    // 2) If there are multiple adjacents, then u-v
    //    is not a bridge
    // Do following steps to check if u-v is a bridge
 
    // 2.a) count of vertices reachable from u
    bool visited[V];
    memset(visited, false, V);
    int count1 = DFSCount(u, visited);
 
    // 2.b) Remove edge (u, v) and after removing
    // the edge, count vertices reachable from u
    rmvEdge(u, v);
    memset(visited, false, V);
    int count2 = DFSCount(u, visited);
 
    // 2.c) Add the edge back to the graph
    addEdge(u, v);
 
    // 2.d) If count1 is greater, then edge (u, v)
    // is a bridge
    return (count1 > count2)? false: true;
}
 
// This function removes edge u-v from graph.
// It removes the edge by replacing adjacent
// vertex value with -1.
void Graph::rmvEdge(int u, int v)
{
    // Find v in adjacency list of u and replace
    // it with -1
    list<int>::iterator iv = find(adj[u].begin(),
                                adj[u].end(), v);
    *iv = -1;
 
 
    // Find u in adjacency list of v and replace
    // it with -1
    list<int>::iterator iu = find(adj[v].begin(),
                                  adj[v].end(), u);
    *iu = -1;
}
 
// A DFS based function to count reachable
// vertices from v
int Graph::DFSCount(int v, bool visited[])
{
    // Mark the current node as visited
    visited[v] = true;
    int count = 1;
 
    // Recur for all vertices adjacent to this vertex
    list<int>::iterator i;
    for (i = adj[v].begin(); i != adj[v].end(); ++i)
        if (*i != -1 && !visited[*i])
            count += DFSCount(*i, visited);
 
    return count;
}
 
// Driver program to test above function
int main()
{
    // Let us first create and test
    // graphs shown in above figure
    Graph g1(4);
    g1.addEdge(0, 1);
    g1.addEdge(0, 2);
    g1.addEdge(1, 2);
    g1.addEdge(2, 3);
    g1.printEulerTour();
 
    Graph g3(4);
    g3.addEdge(0, 1);
    g3.addEdge(1, 0);
    g3.addEdge(0, 2);
    g3.addEdge(2, 0);
    g3.addEdge(2, 3);
    g3.addEdge(3, 1);
 
    // comment out this line and you will see that
    // it gives TLE because there is no possible
    // output g3.addEdge(0, 3);
    g3.printEulerTour();
 
    return 0;
}

Java

// A java program print Eulerian Trail in a
// given Eulerian or Semi-Eulerian Graph
import java.util.*;
 
public class GFG{
 
    // A class that represents an undirected graph
    static class Graph
    {
        // No. of vertices
        int V;
 
        // A dynamic array of adjacency lists
        ArrayList<ArrayList<Integer>> adj;
 
        // Constructor
        Graph(int V)
        {
            this.V = V;
            adj = new ArrayList<ArrayList<Integer>>();
 
            for(int i=0; i<V; i++){
                adj.add(new ArrayList<Integer>());
            }
        }
 
 
        // functions to add and remove edge
        void addEdge(int u, int v)
        {
            adj.get(u).add(v);
            adj.get(v).add(u);
        }
 
        // This function removes edge u-v from graph.
        // It removes the edge by replacing adjacent
        // vertex value with -1.
        void rmvEdge(int u, int v)
        {
            // Find v in adjacency list of u and replace
            // it with -1
            int iv = find(adj.get(u), v);
            adj.get(u).set(iv, -1);
 
 
            // Find u in adjacency list of v and replace
            // it with -1
            int iu = find(adj.get(v), u);
            adj.get(v).set(iu, -1);
        }
 
        int find(ArrayList<Integer> al, int v){
 
            for(int i=0; i<al.size(); i++){
                if(al.get(i) == v){
                    return i;
                }
            }
 
            return -1;
        }
 
        // Methods to print Eulerian tour
        /* The main function that print Eulerian Trail.
        It first finds an odd degree vertex (if there is any)
        and then calls printEulerUtil() to print the path */
        void printEulerTour()
        {
           
            // Find a vertex with odd degree
            int u = 0;
 
            for (int i = 0; i < V; i++){
                if (adj.get(i).size() % 2 == 1)
                {
                    u = i;
                    break;
                }
            }
 
            // Print tour starting from oddv
            printEulerUtil(u);
            System.out.println();
        }
         
        // Print Euler tour starting from vertex u
        void printEulerUtil(int u)
        {
 
            // Recur for all the vertices adjacent to
            // this vertex
            for (int i = 0; i<adj.get(u).size(); ++i)
            {
                int v = adj.get(u).get(i);
 
                // If edge u-v is not removed and it's a
                // valid next edge
                if (v != -1 && isValidNextEdge(u, v))
                {
                    System.out.print(u + "-" + v + " ");
                    rmvEdge(u, v);
                    printEulerUtil(v);
                }
            }
        }
 
        // This function returns count of vertices
        // reachable from v. It does DFS
        // A DFS based function to count reachable
        // vertices from v
        int DFSCount(int v, boolean visited[])
        {
            // Mark the current node as visited
            visited[v] = true;
            int count = 1;
 
            // Recur for all vertices adjacent to this vertex
            for (int i = 0; i<adj.get(v).size(); ++i){
                int u = adj.get(v).get(i);
 
                if (u != -1 && !visited[u]){
                    count += DFSCount(u, visited);
                }
            }
 
            return count;
        }
 
        // Utility function to check if edge u-v
        // is a valid next edge in Eulerian trail or circuit
        // The function to check if edge u-v can be considered
        // as next edge in Euler Tout
        boolean isValidNextEdge(int u, int v)
        {
 
            // The edge u-v is valid in one of the following
            // two cases:
 
            // 1) If v is the only adjacent vertex of u
            int count = 0; // To store count of adjacent vertices
            for (int i = 0; i<adj.get(u).size(); ++i)
                if (adj.get(u).get(i) != -1)
                    count++;
            if (count == 1)
                return true;
 
 
            // 2) If there are multiple adjacents, then u-v
            // is not a bridge
            // Do following steps to check if u-v is a bridge
 
            // 2.a) count of vertices reachable from u
            boolean visited[] = new boolean[V];
            Arrays.fill(visited, false);
            int count1 = DFSCount(u, visited);
 
            // 2.b) Remove edge (u, v) and after removing
            // the edge, count vertices reachable from u
            rmvEdge(u, v);
            Arrays.fill(visited, false);
            int count2 = DFSCount(u, visited);
 
            // 2.c) Add the edge back to the graph
            addEdge(u, v);
 
            // 2.d) If count1 is greater, then edge (u, v)
            // is a bridge
            return (count1 > count2)? false: true;
        }
    }
 
    // Driver program to test above function
    public static void main(String args[])
    {
        // Let us first create and test
        // graphs shown in above figure
        Graph g1 = new Graph(4);
        g1.addEdge(0, 1);
        g1.addEdge(0, 2);
        g1.addEdge(1, 2);
        g1.addEdge(2, 3);
        g1.printEulerTour();
 
        Graph g3 = new Graph(4);
        g3.addEdge(0, 1);
        g3.addEdge(1, 0);
        g3.addEdge(0, 2);
        g3.addEdge(2, 0);
        g3.addEdge(2, 3);
        g3.addEdge(3, 1);
 
        // comment out this line and you will see that
        // it gives TLE because there is no possible
        // output g3.addEdge(0, 3);
        g3.printEulerTour();
    }
}
 
// This code is contributed by adityapande88.

Python3

# A Python program to print Eulerian trail in a
# given Eulerian or Semi-Eulerian Graph
from collections import defaultdict
 
class Graph:
 
    # Constructor and destructor
    def __init__(self, V):
        self.V = V
        self.adj = defaultdict(list)
 
    # functions to add and remove edge
    def addEdge(self, u, v):
        self.adj[u].append(v)
        self.adj[v].append(u)
 
    def rmvEdge(self, u, v):
        self.adj[u].remove(v)
        self.adj[v].remove(u)
 
    # Methods to print Eulerian tour
    def printEulerTour(self):
        # Find a vertex with odd degree
        u = 0
        for i in range(self.V):
            if len(self.adj[i]) % 2 == 1:
                u = i
                break
         
        # Print tour starting from oddv
        self.printEulerUtil(u)
        print()
 
    def printEulerUtil(self, u):
        # Recur for all the vertices adjacent to this vertex
        for v in self.adj[u]:
            # If edge u-v is not removed and it's a valid next edge
            if v != -1 and self.isValidNextEdge(u, v):
                print(u, "-", v, " ", end="")
                self.rmvEdge(u, v)
                self.printEulerUtil(v)
 
    # The function to check if edge u-v can be considered
    # as next edge in Euler Tout
    def isValidNextEdge(self, u, v):
        # The edge u-v is valid in one of the following
        # two cases:
 
        # 1) If v is the only adjacent vertex of u
        count = 0  # To store count of adjacent vertices
        for i in self.adj[u]:
            if i != -1:
                count += 1
        if count == 1:
            return True
 
        # 2) If there are multiple adjacents, then u-v is not a bridge
        # Do following steps to check if u-v is a bridge
        # 2.a) count of vertices reachable from u
        visited = [False] * (self.V)
        count1 = self.DFSCount(u, visited)
 
        # 2.b) Remove edge (u, v) and after removing
        # the edge, count vertices reachable from u
        self.rmvEdge(u, v)
        visited = [False] * (self.V)
        count2 = self.DFSCount(u, visited)
 
        # 2.c) Add the edge back to the graph
        self.addEdge(u, v)
 
        # 2.d) If count1 is greater, then edge (u, v) is a bridge
        return False if count1 > count2 else True
 
    # A DFS based function to count reachable vertices from v
   
    def DFSCount(self, v, visited):
        # Mark the current node as visited
        visited[v] = True
        count = 1
        # Recur for all the vertices adjacent to this vertex
        for i in self.adj[v]:
            if not visited[i]:
                count += self.DFSCount(i, visited)
        return count
    # utility function to form edge between two vertices
    # source and dest
    def makeEdge(src, dest):
        graph.addEdge(src, dest)
 
# Driver program to test above functions
def main():
    # Let us first create and test
    # graphs shown in above figure
    g1 = Graph(4)
    g1.addEdge(0, 1)
    g1.addEdge(0, 2)
    g1.addEdge(1, 2)
    g1.addEdge(2, 3)
    g1.printEulerTour()
  
    g3 = Graph(4)
    g3.addEdge(0, 1)
    g3.addEdge(1, 0)
    g3.addEdge(0, 2)
    g3.addEdge(2, 0)
    g3.addEdge(2, 3)
    g3.addEdge(3, 1)
 
    # comment out this line and you will see that
    # it gives TLE because there is no possible
    # output g3.addEdge(0, 3);
    g3.printEulerTour()
 
if __name__ == "__main__":
    main()
 
    # This code is contributed by vikramshirsath177

Javascript

// A Javascript program print Eulerian Trail in a given
// Eulerian or Semi-Eulerian Graph
 
      // A class that represents an undirected graph
      class Graph {
        constructor(V) {
          this.V = V; // No. of vertices
          //A dynamic array of adjacency lists
          this.adj = Array.from(Array(V), () => new Array());
        }
 
        // functions to add and remove edge
        addEdge(u, v) {
          this.adj[u].push(v);
          this.adj[v].push(u);
        }
 
        // This function removes edge u-v from graph.
        // It removes the edge by replacing adjacent
        // vertex value with -1.
        rmvEdge(u, v) {
          // Find v in adjacency list of u and replace
          // it with -1
 
          for (let i = 0; i < this.adj[u].length; i++) {
            if (this.adj[u][i] == v) {
              this.adj[u][i] = -1;
              break;
            }
          }
 
          // Find u in adjacency list of v and replace
          // it with -1
 
          for (let i = 0; i < this.adj[v].length; i++) {
            if (this.adj[v][i] == u) {
              this.adj[v][i] = -1;
              break;
            }
          }
        }
 
        // Methods to print Eulerian tour
        printEulerTour() {
          // Find a vertex with odd degree
          let u = 0;
 
          for (let i = 0; i < this.V; i++)
            if (this.adj[i].length & 1) {
              u = i;
              break;
            }
 
          // Print tour starting from oddv
          this.printEulerUtil(u);
          console.log("   ");
        }
 
        //Print Euler tour starting from vertex u
        printEulerUtil(u) {
          {
            // Recur for all the vertices adjacent to
            // this vertex
 
            for (let j in this.adj[u]) {
              let v = this.adj[u][j];
 
              // If edge u-v is not removed and it's a
              // valid next edge
              if (v != -1 && this.isValidNextEdge(u, v)) {
                console.log(u + "-" + v);
                this.rmvEdge(u, v);
                this.printEulerUtil(v);
              }
            }
          }
        }
 
        // This function returns count of vertices
        // reachable from v. It does DFS
        DFSCount(v, visited) {
          // Mark the current node as visited
          visited[v] = true;
          let count = 1;
 
          // Recur for all vertices adjacent to this vertex
 
          for (let j in this.adj[v]) {
            let i = this.adj[v][j];
            if (i != -1 && !visited[i]) count += this.DFSCount(i, visited);
          }
          return count;
        }
 
        // The function to check if edge u-v can be considered
        // as next edge in Euler Tout
        isValidNextEdge(u, v) {
          // The edge u-v is valid in one of the following
          // two cases:
 
          // 1) If v is the only adjacent vertex of u
          let count = 0; // To store count of adjacent vertices
 
          for (let j in this.adj[u]) {
            let i = this.adj[u][j];
            if (i != -1) count++;
          }
          if (count == 1) return true;
 
          // 2) If there are multiple adjacents, then u-v
          //    is not a bridge
          // Do following steps to check if u-v is a bridge
 
          // 2.a) count of vertices reachable from u
          let visited = new Array(this.V);
          visited.fill(false);
          let count1 = this.DFSCount(u, visited);
 
          // 2.b) Remove edge (u, v) and after removing
          // the edge, count vertices reachable from u
          this.rmvEdge(u, v);
          visited.fill(false);
          let count2 = this.DFSCount(u, visited);
 
          // 2.c) Add the edge back to the graph
          this.addEdge(u, v);
 
          // 2.d) If count1 is greater, then edge (u, v)
          // is a bridge
          return count1 > count2 ? false : true;
        }
      }
 
      // Driver program to test above function
 
      // Let us first create and test
      // graphs shown in above figure
      let g1 = new Graph(4);
      g1.addEdge(0, 1);
      g1.addEdge(0, 2);
      g1.addEdge(1, 2);
      g1.addEdge(2, 3);
      g1.printEulerTour();
 
      let g3 = new Graph(4);
      g3.addEdge(0, 1);
      g3.addEdge(1, 0);
      g3.addEdge(0, 2);
      g3.addEdge(2, 0);
      g3.addEdge(2, 3);
      g3.addEdge(3, 1);
 
      // comment out this line and you will see that
      // it gives TLE because there is no possible
      // output g3.addEdge(0, 3);
      g3.printEulerTour();

C#

// A C# program print Eulerian Trail in a
// given Eulerian or Semi-Eulerian Graph
using System;
using System.Collections.Generic;
 
class GFG {
   
    // A class that represents an undirected graph
    class Graph {
       
        // No. of vertices
        int V;
       
        // A dynamic array of adjacency lists
        List<List<int> > adj;
 
        // Constructor
        public Graph(int V)
        {
            this.V = V;
            adj = new List<List<int> >();
 
            for (int i = 0; i < V; i++) {
                adj.Add(new List<int>());
            }
        }
 
        public void addEdge(int u, int v)
        {
            adj[u].Add(v);
            adj[v].Add(u);
        }
 
        // This function removes edge u-v from graph.
        // It removes the edge by replacing adjacent
        // vertex value with -1.
        public void rmvEdge(int u, int v)
        {
           
            // Find v in adjacency list of u and replace
            // it with -1
            int iv = adj[u].IndexOf(v);
            adj[u][iv] = -1;
           
    // Find u in adjacency list of v and replace
            // it with -1
            int iu = adj[v].IndexOf(u);
            adj[v][iu] = -1;
        }
 
        int find(List<int> al, int v)
        {
            for (int i = 0; i < al.Count; i++) {
                if (al[i] == v) {
                    return i;
                }
            }
            return -1;
        }
 
        // Methods to print Eulerian tour
        /* The main function that print Eulerian Trail.
        It first finds an odd degree vertex (if there is any)
        and then calls printEulerUtil() to print the path */
        public void printEulerTour()
        {
           
            // Find a vertex with odd degree
            int u = 0;
            for (int i = 0; i < V; i++) {
                if (adj[i].Count % 2 == 1) {
                    u = i;
                    break;
                }
            }
           
            // Print tour starting from oddv
            printEulerUtil(u);
            Console.WriteLine();
        }
 
        // Print Euler tour starting from vertex u
        void printEulerUtil(int u)
        {
           
            // Recur for all the vertices adjacent to
            // this vertex
            for (int i = 0; i < adj[u].Count; ++i) {
                int v = adj[u][i];
               
                // If edge u-v is not removed and it's a
                // valid next edge
                if (v != -1 && isValidNextEdge(u, v)) {
                    Console.Write(u + "-" + v + " ");
                    rmvEdge(u, v);
                    printEulerUtil(v);
                }
            }
        }
 
       
         // This function returns count of vertices
        // reachable from v. It does DFS
        // A DFS based function to count reachable
        // vertices from v
        int DFSCount(int v, bool[] visited)
        {
           
            // Mark the current node as visited
            visited[v] = true;
            int count = 1;
           
            // Recur for all vertices adjacent to this vertex
            for (int i = 0; i < adj[v].Count; ++i) {
                int u = adj[v][i];
 
                if (u != -1 && !visited[u]) {
                    count += DFSCount(u, visited);
                }
            }
            return count;
        }
 
       
        // Utility function to check if edge u-v
        // is a valid next edge in Eulerian trail or circuit
        // The function to check if edge u-v can be considered
        // as next edge in Euler Tout
        bool isValidNextEdge(int u, int v)
        {
           
            // The edge u-v is valid in one of the following
            // two cases:
           
            // 1) If v is the only adjacent vertex of u
            int count = 0; // To store count of adjacent vertices
            for (int i = 0; i < adj[u].Count; ++i)
                if (adj[u][i] != -1)
                    count++;
            if (count == 1)
                return true;
           
             // 2) If there are multiple adjacents, then u-v
            // is not a bridge
            // Do following steps to check if u-v is a bridge
 
            // 2.a) count of vertices reachable from u
            bool[] visited = new bool[V];
            Array.Fill(visited, false);
            int count1 = DFSCount(u, visited);
           
            // 2.b) Remove edge (u, v) and after removing
            // the edge, count vertices reachable from u
            rmvEdge(u, v);
            Array.Fill(visited, false);
            int count2 = DFSCount(u, visited);
           
            // 2.c) Add the edge back to the graph
            addEdge(u, v);
           
            // 2.d) If count1 is greater, then edge (u, v)
            // is a bridge
            return (count1 > count2) ? false : true;
        }
    }
 
   
     // Driver program to test above function
    public static void Main()
    {
       
        // Let us first create and test
        // graphs shown in above figure
        Graph g1 = new Graph(4);
        g1.addEdge(0, 1);
        g1.addEdge(0, 2);
        g1.addEdge(1, 2);
        g1.addEdge(2, 3);
        g1.printEulerTour();
        Graph g3 = new Graph(4);
        g3.addEdge(0, 1);
        g3.addEdge(1, 0);
        g3.addEdge(0, 2);
        g3.addEdge(2, 0);
        g3.addEdge(2, 3);
        g3.addEdge(3, 1);
       
        // comment out this line and you will see that
        // it gives TLE because there is no possible
        // output g3.addEdge(0, 3);
        g3.printEulerTour();
    }
}
// This code is contributed by Prajwal Kandekar

Output:

2-0  0-1  1-2  2-3  
1-0  0-2  2-3  3-1  1-0  0-2

Time Complexity: O(V+E)
The time complexity of the above algorithm is O(V+E) where V is the number of vertices and E is the number of edges in the graph.

Space Complexity: O(V+E)
The space complexity of the above algorithm is O(V+E) where V is the number of vertices and E is the number of edges in the graph.

egoista

Improve

Tarjan's Algorithm to find Strongly Connected Components

Dynamic Connectivity | Set 1 (Incremental)

BFS and DFS on Graph

Cycle in a Graph

Shortest Paths in Graph

Minimum Spanning Tree in Graph

Topological Sorting in Graph

Connectivity of Graph

Maximum flow in a Graph

Some must do problems on Graph

Paths to travel each nodes using each edge (Seven Bridges of Königsberg)

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Java

Python3

Javascript

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