Python Program to Convert String Matrix Representation to Matrix
Last Updated :
02 May, 2023
Given a String with matrix representation, the task here is to write a python program that converts it to a matrix.
Input : test_str = “[gfg,is],[best,for],[all,geeks]”
Output : [[‘gfg’, ‘is’], [‘best’, ‘for’], [‘all’, ‘geeks’]]
Explanation : Required String Matrix is converted to Matrix with list as data type.
Input : test_str = “[gfg,is],[for],[all,geeks]”
Output : [[‘gfg’, ‘is’], [‘for’], [‘all’, ‘geeks’]]
Explanation : Required String Matrix is converted to Matrix with list as data type.
Method 1 : Using split() and regex expression
In this, a plain list is constructed using appropriate regex expression and split() performs the task of getting inner dimension for 2D Matrix.
Example:
Python3
import re
test_str = "[gfg,is],[best,for],[all,geeks]"
print("The original string is : " + str(test_str))
flat_1 = re.findall(r"\[(.+?)\]", test_str)
res = [sub.split(",") for sub in flat_1]
print("The type of result : " + str(type(res)))
print("Converted Matrix : " + str(res))
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Output
The original string is : [gfg,is],[best,for],[all,geeks]
The type of result : <class 'list'>
Converted Matrix : [['gfg', 'is'], ['best', 'for'], ['all', 'geeks']]
Method 2 : Using json.loads()
In this, the task of conversion to the matrix is done using the unbuilt method of loads() of JSON library.
Example:
Python3
import json
test_str = '[["gfg", "is"], ["best", "for"], ["all", "geeks"]]'
print("The original string is : " + str(test_str))
res = json.loads(test_str)
print("The type of result : " + str(type(res)))
print("Converted Matrix : " + str(res))
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Output
The original string is : [["gfg", "is"], ["best", "for"], ["all", "geeks"]]
The type of result : <class 'list'>
Converted Matrix : [['gfg', 'is'], ['best', 'for'], ['all', 'geeks']]
Method 3: Using string manipulation and list comprehension
We can use string manipulation to extract the individual elements of the matrix, and then use a list comprehension to create a new matrix with those elements.
Algorithm:
1. Remove the square brackets from the string using string manipulation.
2. Split the string into rows using the comma and newline characters as delimiters.
3. Split each row into its individual elements using the comma as a delimiter.
4. Create a new matrix with the elements using a list comprehension.
Python3
test_str = "[gfg,is],[best,for],[all,geeks]"
rows = test_str[1:-1].split("],[")
matrix = []
for row in rows:
elements = row.split(",")
matrix.append(elements)
print(matrix)
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Output
[['gfg', 'is'], ['best', 'for'], ['all', 'geeks']]
Time complexity: O(n)
Space complexity: O(n)
Method 4: Use a combination of re.findall() and re.split() functions from the re module.
Step-by-step approach:
- Import the re module.
- Define a test string test_str containing comma-separated values inside brackets.
- Use the re.findall() function with the pattern r’\[([^]]+)\]’ to find all comma-separated values inside brackets in the test_str string. This pattern matches an opening bracket (\[), followed by one or more characters that are not a closing bracket ([^]]+), followed by a closing bracket (\]).
- Store the resulting list of strings in the values variable.
- Use a list comprehension to split each value string into a list of strings using the re.split() function with a comma as the separator. The resulting list of lists is stored in the matrix
- variable.Print the matrix variable to display the resulting matrix.
Python3
import re
test_str = "[gfg,is],[best,for],[all,geeks]"
values = re.findall(r'\[([^]]+)\]', test_str)
matrix = [re.split(',', value) for value in values]
print(matrix)
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Output
[['gfg', 'is'], ['best', 'for'], ['all', 'geeks']]
Time complexity: O(n), where n is the length of the input string.
Auxiliary space: O(n), where n is the length of the input string.
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