Lambda with if but without else in Python
Last Updated :
06 Oct, 2021
In Python, Lambda function is an anonymous function, which means that it is a function without a name. It can have any number of arguments but only one expression, which is evaluated and returned. It must have a return value.
Since a lambda function must have a return value for every valid input, we cannot define it with if but without else as we are not specifying what will we return if the if-condition will be false i.e. its else part.
Let’s understand this with a simple example of lambda function to square a number only if it is greater than 0 using if but without else.
Example #1:
Python3
square = lambda x : x*x if(x > 0)
print(square(6))
|
Output:
File "/home/2c8c59351e1635b6b026fb3c7fc17c8f.py", line 2
square = lambda x : x*x if(x > 0)
^
SyntaxError: invalid syntax
The above code on execution shows SyntaxError, as we know that a lambda function must return a value and this function returns x*x if x > 0 and it does not specify what will be returned if the value of x is less than or equal to 0.
To correct it, we need to specify what will be returned if the if-condition will be false i.e. we must have to specify its else part.
Let’s see the above code with its else part.
Code:
Python3
square = lambda x : x*x if(x > 0) else None
print(square(4))
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Output:
16
Example #2: The first code is with if but without else then second is with if-else.
Python3
mod = lambda x : x if(x >= 0)
print(mod(-1))
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Output:
File "/home/20b09bdd29e24dfe24c185cd99dfcdfa.py", line 2
mod = lambda x : x if(x >= 0)
^
SyntaxError: invalid syntax
Now, let’s see it using if-else.
Python3
mod = lambda x : x if(x >= 0) else -x
print(mod(-1))
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Output:
1
Example #3: The first code is with if but without else then second is with if-else.
Python3
max = lambda a, b : x if(a > b)
print(max(1, 2))
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Output:
File "/home/8cf3856fc13d0ce75edfdd76793bdde4.py", line 2
max = lambda a, b : x if(a > b)
^
SyntaxError: invalid syntax
Now, let’s see it using if-else.
Python3
max = lambda a, b : a if(a > b) else b
print(max(1, 2))
print(max(10, 2))
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Output:
2
10
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