How to create an empty class in Python?
Last Updated :
29 Dec, 2020
A class is a user-defined blueprint or prototype from which objects are created. Class can be considered as a user-defined data type. Generally, a class contains data members known as attributes of the class and member functions that are used to modify the attributes of the class. But have you ever wondered how to define an empty class i.e a class without members and member functions?
In Python, if we write something like the following, it would raise a SyntaxError
.
Output:
File "gfg.py", line 5
^
SyntaxError: unexpected EOF while parsing
In Python, to write an empty class pass
statement is used. pass
is a special statement in Python that does nothing. It only works as a dummy statement. However, objects of an empty class can also be created.
Example:
class Geeks:
pass
obj = Geeks()
print (obj)
|
Output:
<__main__.Geeks object at 0x02B4A340>
Python also allows us to set the attributes of an object of an empty class. We can also set different attributes for different objects. See the following example for better understanding.
class Employee:
pass
obj1 = Employee()
obj1.name = 'Nikhil'
obj1.office = 'GeeksforGeeks'
obj2 = Employee()
obj2.name = 'Abhinav'
obj2.office = 'GeeksforGeeks'
obj2.phone = 1234567889
print ( "obj1 Details:" )
print ( "Name:" , obj1.name)
print ( "Office:" , obj1.office)
print ()
print ( "obj2 Details:" )
print ( "Name:" , obj2.name)
print ( "Office:" , obj2.office)
print ( "Phone:" , obj2.phone)
|
Output:
obj1 Details:
Name: Nikhil
Office: GeeksforGeeks
obj2 Details:
Name: Abhinav
Office: GeeksforGeeks
Phone: 1234567889
Traceback (most recent call last):
File "gfg.py", line 34, in
print("Phone:", obj1.phone)
AttributeError: 'Employee' object has no attribute 'phone'
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