Python program to find the type of IP Address using Regex
Last Updated :
02 Sep, 2021
Prerequisite: Python Regex
Given an IP address as input, write a Python program to find the type of IP address i.e. either IPv4 or IPv6. If the given is neither of them then print neither.
What is an IP (Internet Protocol) Address?
Every computer connected to the Internet is identified by a unique four-part string, known as its Internet Protocol (IP) address. IPv4 and IPv6 are internet protocol version 4 and internet protocol version 6, IP version 6 is the new version of Internet Protocol, which is way better than IP version 4 in terms of complexity and efficiency.
- IPv4 was the primary version brought into action for production within the ARPANET in 1983. IP version four addresses are 32-bit integers which will be expressed in hexadecimal notation.
- IPv6 was developed by the Internet Engineering Task Force (IETF) to deal with the problem of IP v4 exhaustion. IP v6 is 128-bits address having an address space of 2128, which is way bigger than IPv4. In IPv6 we use Colon-Hexa representation. There are 8 groups and each group represents 2 Bytes.
Examples:
Input: 192.0.2.126
Output: IPv4
Input: 3001:0da8:75a3:0000:0000:8a2e:0370:7334
Output: IPv6
Input: 36.12.08.20.52
Output: Neither
Approach:
- Take the IP address as input.
- Now, check if this IP address resembles IPv4 type addresses using regex.
- If yes, then print “IPv4” else check if this IP address resembles IPv6 type addresses using regex.
- If yes, then print “IPv6”.
- If the address doesn’t resemble any of the above types then we will print “Neither”.
Below is the implementation of the above approach:
Python3
import re
ipv4 =
ipv6 =
def find(Ip):
if re.search(ipv4, Ip):
print ( "IPv4" )
elif re.search(ipv6, Ip):
print ( "IPv6" )
else :
print ( "Neither" )
if __name__ = = '__main__' :
Ip = "192.0.2.126"
find(Ip)
Ip = "3001:0da8:75a3:0000:0000:8a2e:0370:7334"
find(Ip)
Ip = "36.12.08.20.52"
find(Ip)
|
Output:
IPv4
IPv6
Neither
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